Help please ! :<

Hi lovely crocheters of Ribblr :000 I would like to ask how many stitches need to be in a round wait lemme explain more so you guys understand :l so say the pattern said this :
1.DC all (32)
2.DC , dec all (?)
basically what I’m asking is how many stitches are now going to be after you like do DC , Dec ?
The reason why I am asking is bc I’m making a pattern rn (no :< sadly I’m not giving sneek peaks sowyy ) and I kinda did the round wrong and I can’t undo it bc my stitch marker flew off ( it went NEAAAWAWWWMMMMM :dash::dash::dash:) and I don’t know what to do but I would just be helpful if anyone knows how many stitches need to be :<<<
Thank you so much lovely people<333

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I think there should be 30 Stitches if my math’s right!

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If it’s just one dec, then it’ll be 31. Every dec = one less st in the end

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In r2 would it be “double crochet decrease in all stitches?”
If yes, then the stitch count would be “16 stiches” :3

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oh :0 wait I didn’t explain correctly , I meant that DC, dec all the round I’m so sorry :sob:

yea I meant DC , Dec for the whole round sorry :sob::sob:

wait what sorry ?

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So you want the (DC, Dec) repeated around?

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Ye that’s correct

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That will not fit in 32 sts. It would need a multiple of 3. One for the DC, and 2 for the decrease. So, 33.

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Ohh thank you so much :sweat_smile: I thought I went wrong somewhere:>>

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Pretending we started with 33.
(DC, Dec) x 11 = 22

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Yea :)
wowie u do math quicky I could never

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Oh ok but would it work with 3 DC , dec?

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Nope :<

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It would work with 2 DC, dec tho

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If you want it to be 32, you could divide it up like this.

Dec, (DC, Dec) x 10 = 21

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Oh no :<

Ohhhhh tysmmm :>>

Ohh yeaa ty as well <33

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Ok so is it this (dc, Dec)x? =(?) or is it this dc (Dec)x? =(?) what are you needing to know

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Well, it’s kinda hard to answer as it doesn’t come out evenly.

  1. You have 32 stitches in this round.
  2. With DC, dec all, you are taking every 3 stitches and reducing it down to two. 3 does not go into 32 evenly.
    -( it takes 3 stitches to do DC, dec. One for the DC, and 2 stitches combining to one with the Dec)
    So best you have is DC, dec ten times with 2 stitches left unworked.

Solutions: you could do
2. Dec, (DC, dec)x10 ending with 21 stitches, and it keeps the rate of decreases as a constant pattern.
Or You can realize you can divide 32 by 4, so
Maybe try
2. 2DC, dec all (24)

Note, I’ve been trying to use your way of writing, but it really is much clearer if you write rounds using parentheses and include how many times you repeat.
Ex: (2DC, dec)x8. It’s easier for me to figure out the total stitches this way as it becomes a simple math problem.
Starting stitches for:
(2DC, Dec)x8 =
(2 st, 2st)x8 required =
(2+2)x8= (4)x8 = 32 st

Number of ending stitches for:
(2DC, dec)x8 =
(2st, 1 st)x8 =
(2+1)x8 =(3)x8 = 24 stitches left after round.

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Wow. Lots of other awesome answers. No one else’s reply loaded for me for some reason before I replied, so sorry for the repeat answer.

Great minds think alike! :joy:

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Oof tysmmm I might try one of these !

I need to know how many stitches will be on the round after I do DC, Dec

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